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Calculator KB-07

PCB trace width calculator

Find out how wide a PCB trace needs to be for a given current, and how much power it dissipates.

KB-07Trace widthCalculates in real time

Result

Minimum width0.898 mm
Same in mil35.3 mil
Trace cross-sectional area0.0314 mm²
Trace resistance30.06 mΩ
Voltage drop90.2 mV
Trace power loss270.6 mW
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In brief: Calculate PCB trace width based on current and allowable temperature rise per IPC-2221 for external and internal layers, plus resistance and voltage drop. Example: Minimum width: 0.898 mm.

Calculation example

Input data
Current3 A
Allowable trace temperature rise20 °C
Copper thickness35 µm (1 oz)
LayerOuter (air-cooled)
Trace length50 mm
Result
Minimum width0.898 mm
Same in mil35.3 mil
Trace cross-sectional area0.0314 mm²
Trace resistance30.06 mΩ
Voltage drop90.2 mV
Trace power loss270.6 mW

How it is calculated

The calculation uses the empirical formula from the IPC-2221 standard: trace cross-sectional area is determined by current and allowable temperature rise.

A = (I / (k · ΔT0,44))1/0,725 [mil²]
W = A / (T · 1,378) [mil]

Here, k = 0.048 for outer layers and 0.024 for inner layers; T is the copper thickness in ounces. Resistance is calculated for copper heated to 25 °C plus the specified temperature rise.

What to look for

  • The formula is intended for currents up to 35 A, temperature rises of 10–100 °C, and widths up to 10 mm. Outside these limits, the result is approximate.
  • Temperature rise isn't the only constraint. Voltage drop can be an issue in a long trace: check it separately in feedback circuits and controller power supply lines.
  • Adjacent power traces heat each other. Where space allows, make the trace wider than calculated or use a copper pour.

Frequently asked questions

How wide should a trace be for 3 A?

With 35 µm copper on the outer layer and a 20 °C temperature rise, the minimum is about 0.9 mm according to IPC-2221. On an inner layer, it needs to be about 2.6 times wider.

How does copper thickness affect trace width?

It’s inversely proportional: 70 µm instead of 35 µm lets you make the trace half as wide at the same current and temperature rise.

How much current can a 1 mm-wide trace handle?

About 3.2 A on an outer layer with 35 µm copper and a 20 °C temperature rise. For long traces, also check the voltage drop.

Updated · kirich.blog · The calculation runs in your browser; no data is sent anywhere.

See also